微机原理与汇编语言复习题及参考答案.doc

微机原理与汇编语言复****题及参考答案                                ——CSDN下载频道提供,请尊重原创一、选择题:=0A8H,CX=2,CF=1,执行RCL AL,CL指令后,AL中的值为       (   )                                                                            (   )MOV AL,0C2HAND AL,=40H       =20H       =0C0H     =                           (  ) ,1          ,1       ,2ROLCL,1                    SHLCL,1         SHLCL,,若要使BH中的数一定为奇数,应执行的指( ) BH,01H  BH,01H    BH,01H  BH,01H (AL)=37H,(BL)=95H,执行指令IMULBL后(AX)=           (    )                     ,错误的操作是                               (   ) SS:[BX+DI],1000H          DX,1000H  WORDPTR[BX],1000H       DS,                              ( )    ,可以作为它的段地址有               ( )                                                  ( )                                         ( ),25H ,BL   :[25],、间接、立即三种寻址方式指令的执行速度,由决至慢的排序为           ( )、立即、间接           、间接、、直接、间接          ,当执行完指令CALLAX后,栈顶的物理地址是(   )                         ,标志位CF和OF的值是           ( )MOVAX,OC126HMOVBX,5AB7HSUBAX,,0          ,1           ,0       ,(D)。           +SI的内容         +[SI],10[BX]的源操作数的寻址方式是              ( )                    MOVAX, AX【BX+DI】(只能用BX,BP;SI和DI)   。                          ()+25D                   +-102Q                  *                   ( )                                ()                           =1