物理化学 何杰 课后答案[1-11章].khda(1).pdf

1 1 9 V T p V T V V 1 T T p V V 1 V T ,V=nRT/p, T p nR nRT p T V V p V 1 1 T V 1 p T 1 (C 2H 3Cl) 300 m 3 90kg h 0 M W= PV=nRT, PV=mRT/ M W = = kgm -3 27 1 2 9 g 4 g 25 g 1 gcm 3 V= =100cm 3 pV=nRT, PV= M W gmol -1 V 100 0 75 g 75 gmol mol -1-1 0 1 3 9 20 200cm 3 g ( ) ( ) y( )= p( )= kPa y( )= p( )= 0 (CH 3Cl) p p/ p/kPa /gdm -3 M RT VM mRT p p RT M 0 /p 325 67 325 67 )=0 )=0 550 50 550 50 3074 1 3074 15263 1 MM RT RT VM RT 1 4 9 p p CH 3Cl B p B 50 1 7 9 25 40dm 3 10 2 kPa Z PV=ZnRT n= 11kg T B T B T B=a/(bR) a b dm dm 33 1 8 9 T= T= P T= = K 40dm 3 10 2 kPa 300 kPa 12 m 3 = 1 9 9 Z= n = 1977kPa <END>.