Population Standard Deviation of a Discrete Random Variable一个离散型随机变量的总体标准偏差.ppt
Population Standard Deviation of a Discrete Random Variable一个离散型随机变量的总体标准偏差 (cont.) Standard Deviation of a DiscrX+a) = SD(X) Example: a = -1 Var(X+a)=Var(X-1)=Var(X) SD(X+a)=SD(X-1)=SD(X) Probability Great
10+2 P(X=x4) X+2 x1+2 x2+2 x3+2 x4+2 P P(X=x1) P(X=x2) P(X=x3) E(x + a) = E(x) + a; SD(x + a)=SD(x); let a = 2 m= = m= = New Expected Value Long (UNC-CH) way: (compute from “scratch”) E(x+2)=12(.20)+7(.40)+3(.25)+(-2)(.15) = Smart (NCSU) way: a=2; E(x+2) =E(x) + 2 = + 2 = New Variance and SD Long (UNC-CH) way: (compute from “scratch”) Var(X+2)=(12-)2()+… +(-2+)2() = SD(X+2) = √ = Smart (NCSU) way: Var(X+2) = Var(X) = SD(X+2) = SD(X) = Rules for E(X), Var(X) and SD(X): multiplying by constant b E(bX)=b E(X) Var(b X) = b2Var(X) SD(bX)= |b|SD(X) Example: b =-1 E(bX)=E(-X)=-E(X) Var(bX)=Var(-1X)= =(-1)2Var(X)=Var(X) SD(bX)=SD(-1X)= =|-1|SD(X)=SD(X) Expected Value and SD of Linear Transformation a + bx Let X=number of repairs a new computer needs each year. Suppose E(X)= and SD(X)= The service contract for the computer offers unlimited repairs for $100 per year plus a $25 service charge for each repair. What are the mean and standard deviation of the yearly cost of the service contract? Cost = $100 + $25X E(cost) = E($100+$25X)=$100+$25E(X)=$100+$25*= = $100+$5=$105 SD(cost)=SD($100+$25X)=SD($25X)=$25*SD(X)=$25*= =$ Addition and Subtraction Rules for Random Variables E(X+Y) = E(X) + E(Y); E(X-Y) = E(X) - E(Y) When X and Y are independent random variables: Var(X+Y)=Var(X)+Var(Y) SD(X+Y)= SD’s do not add: SD(X+Y)≠ SD(X)+SD(Y) Var
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