Stoichiometry Involving Molar Concentration:涉及的摩尔浓度的化学计量比 What is Stoichiometry? Stoichiometry is the relationships y Convert given quantity to # of mol of quantity If given quantity in L: use STP to convert STP= 1 mol/ L If given quantity in particles: Use Avogadro’s Number to convert × 10^23 Step 2: Balance the Equation 2Al(s) + 2NaOH(aq) + 2H2O(l) 2NaAlO2(aq) + 3H2(g) Step 3: Find mole of given quantity Given quantity: Hydrogen gas at STP. Moles of H2 = (1mol/) = mol H2 Step 4: Molar Ratio Moles of given quantity: mol of H2 Moles of wanted quantity: ? Mol of NaOH 2Al(s) + 2NaOH(aq) + 2H2O(l) -> 2NaAlO2(aq) + 3H2(g) 2 : 3 ratio (mol of NaOH: mol of H2) 2:3 = 2/3 Mol(NaOH)= mol H2 (2 mol NaOH/3 mol H2)= mol NaOH What volume of NaOH solution is required? mol NaOH (step 4 answer) sodium hydroxide (NaOH) solution (given) Volume(v) = Mole(n)/ Concentration(c) (Rearranged Molarity equation) Volume of NaOH = ( mol) / () = NaOH You Are Done! Answer: of Sodium Hydroxide (NaOH) solution was required. ALL IT TAKES IS THESE 5 SPECIAL STEPS! Still having troubles remembering how to do these questions? NO WORRIES! We have a song to help you! If I were a Mole Lyrics *Tune: ‘If I were a Boy’ by Beyonce Knowles If I were a mole even just for a day I’d get up every morning just to Do stoichiometry problems…
I love those questions With molar concentration Except I always had a Secret to solving all these tricky ones. If I were a mole I could always understand How you could solve this question With five really ea-s-y steps Remember tha-at Molar Concentration Is c equals n over v It’s also called molarity And you can use STP to solve If I were a mole The first big step is to Write out a proper equation With all the right element symbols Step two is to-oo Balance the equation both sides ‘cause all elements need to have sam