一:Struts2入门:视图:jsp()控制器:StrutsPrepareAndExecuteFilter,(过滤器)中。模型:action(LoginAction)那个FilterDispatcher是struts1的,struts2的是StrutsPrepareAndExecuteFilter在这里,我不知道的是如何实例化的,.?<%***@pagelanguage="java"import=".*"pageEncoding="UTF-8"%><%Stringpath=();StringbasePath=()+"://"+()+":"+()+path+"/";%><!DOCTYPEHTMLPUBLIC"-//W3C////EN"><html><head><basehref="<%=basePath%>"><title>MyJSP''startingpage</title></head><body><formaction=""><inputtype="text"name="username"><inputtype="submit"name="submit"></form></body></html><?xmlversion=""encoding="UTF-8"?><web-appversion="" xmlns="http://java./xml/ns/javaee" xmlns:xsi="1/XMLSchema-instance" xsi:schemaLocation="http://java./xml/ns/javaee http://java./xml/ns/javaee/web-"> <filter> <filter-name>struts2</filter-name> <filter-.</filter-class> </filter> <filter-mapping> <filter-name>struts2</filter-name> <url-pattern>/*</url-pattern> </filter-mapping><e-file-list><e-file></e-file></e-file-list></web-app><?xmlversion=""encoding="UTF-8"?><!DOCTYPEstrutsPUBLIC"-//ApacheSoftwareFoundation////EN""http://struts./dtds/struts-"><struts><packagename="struts2"extends="struts-default"><actionname="loginaction"class=""><resultname="ess">/</result></action></package></struts>.;.;lassLoginActionextendsActionSupport{ privateStringusername; publicStringpassword; publicStringgetUsername(){ returnusername; } publicvoidsetUsername(Stringusername){ =username; } ***@Override publicStringexecute()throwsException{ //TODOAuto-generatedmethodstub ESS; }}<%***@pagelanguage="java"import=".*"pageEncoding="UTF-8"%><%Stringpath=
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