展厅 7 11- k 展厅 8 2- b 5- e 9- i 13- m 展厅 3 3- c 展厅 4 7- g 展厅 5 10- j 展厅 6 1- a 4- d 8- h 12- l 展厅 1 6- f 展厅 2 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% 大 %% 家仿照这个把第一题枚举出来~~ %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% 以 %% 下是程序 %% 先 %% 在作业题的图的 13 个位置上标注 a,b,c... 等编号 tic; clc; clear all; position=[]; for a=0:1; for b=0:1; for c=0:1; for d=0:1; for e=0:1; for f=0:1; for g=0:1 for h=0:1; for i=0:1; for j=0:1; for k=0:1; for l=0:1; for m=0:1; 进 %% 行约束条件判断,将可行解先挑出来 %% if (a+d+f>=1)&(f+h+l>=1)&(a+b+c>=1)&(c+d+e+g>=1)&(g+h+i+j>=1)&(j+m+l>=1) &(b+e+i+k>=1)&(k+m>=1) 满 %% 足条件(即所有展厅均可监控到)的可行解找出来,并求出摄象头数 %% plus=sum([a b c d e f g h i j k l m